x^2+0.00125x=0.999375

Solution for x^2+0.00125x=0.999375 equation:

x^2+0.00125x=0.999375

We move all terms to the left:

x^2+0.00125x-(0.999375)=0

We add all the numbers together, and all the variables

x^2+0.00125x-0.999375=0

a = 1; b = 0.00125; c = -0.999375;
Δ = b2-4ac
Δ = 0.001252-4·1·(-0.999375)
Δ = 3.9975015625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.00125)-\sqrt{3.9975015625}}{2*1}=\frac{-0.00125-\sqrt{3.9975015625}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.00125)+\sqrt{3.9975015625}}{2*1}=\frac{-0.00125+\sqrt{3.9975015625}}{2}
$